(-3y+1)(4y^2-y-7)=0

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Solution for (-3y+1)(4y^2-y-7)=0 equation: 


Simplifying
(-3y + 1)(4y2 + -1y + -7) = 0

Reorder the terms:
(1 + -3y)(4y2 + -1y + -7) = 0

Reorder the terms:
(1 + -3y)(-7 + -1y + 4y2) = 0

Multiply (1 + -3y) * (-7 + -1y + 4y2)
(1(-7 + -1y + 4y2) + -3y * (-7 + -1y + 4y2)) = 0
((-7 * 1 + -1y * 1 + 4y2 * 1) + -3y * (-7 + -1y + 4y2)) = 0
((-7 + -1y + 4y2) + -3y * (-7 + -1y + 4y2)) = 0
(-7 + -1y + 4y2 + (-7 * -3y + -1y * -3y + 4y2 * -3y)) = 0
(-7 + -1y + 4y2 + (21y + 3y2 + -12y3)) = 0

Reorder the terms:
(-7 + -1y + 21y + 4y2 + 3y2 + -12y3) = 0

Combine like terms: -1y + 21y = 20y
(-7 + 20y + 4y2 + 3y2 + -12y3) = 0

Combine like terms: 4y2 + 3y2 = 7y2
(-7 + 20y + 7y2 + -12y3) = 0

Solving
-7 + 20y + 7y2 + -12y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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